MySQL MEMBER OF() Function
In MySQL, the MEMBER OF() function checks whether a specified value is an element of a JSON array.
MEMBER OF() Syntax
Here is the syntax of the MySQL MEMBER OF() function:
value MEMBER OF(json_array)
Parameters
value-
Required. The value to check. It can be of any type.
json_array-
Required. The JSON array.
Return value
If json_array contains value, MEMBER OF() returns 1, otherwise returns 0.
The MEMBER OF() function returns 1 if both value and json_array are scalar and equal.
MySQL will give an error if the parameter json_array is not a valid JSON document. You can use JSON_VALID() to verify the JSON document.
MEMBER OF() Examples
Basic usage
SELECT
1 MEMBER OF('[1, 2, "a"]'),
'a' MEMBER OF('[1, 2, "a"]');
+----------------------------+------------------------------+
| 1 MEMBER OF('[1, 2, "a"]') | 'a' MEMBER OF('[1, 2, "a"]') |
+----------------------------+------------------------------+
| 1 | 1 |
+----------------------------+------------------------------+scalars
The MEMBER OF() function returns 1 if both value and json_array are scalar and equal.
SELECT
1 MEMBER OF('1'),
'a' MEMBER OF('"a"'),
CAST('true' AS JSON) MEMBER OF('true');
+------------------+----------------------+----------------------------------------+
| 1 MEMBER OF('1') | 'a' MEMBER OF('"a"') | CAST('true' AS JSON) MEMBER OF('true') |
+------------------+----------------------+----------------------------------------+
| 1 | 1 | 1 |
+------------------+----------------------+----------------------------------------+Here, we used the CAST() function to convert 'true' from a string to a JSON value.